$3x^3-6ax^2-45a^2x$
$+8+\left(-1\right)\cdot\left(+6\right)$
$\int\frac{\tan^5x}{\sec^8x}dx$
$-50-50-50-50-50-50-50$
$\int8x\left(x+2\right)^{\frac{1}{2}}dx$
$-48-14+22-16+8$
$x^2\left(3y^3\right)x\:2\:$
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