$-1+5-3+12-7-6-8-9+2+6$
$x^3-b^9$
$8\left(\sqrt[3]{\frac{x}{6}}\right)^2$
$\lim_{x\to-\infty}\frac{\sqrt{2x^4-2x^3-1}}{2-3x^2}$
$25.3+24.66$
$\left(2x+3y\right)\left(2x-3y\right)-3\left(x+2y\right)\left(x-2y\right)$
$4\left(3-x\right)+2x+3$
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