$\left(-4x+2y+3\right)\left(2x+3y+2\right)$
$\frac{a^2}{9}+\frac{ab}{3}+\frac{b^2}{4}$
$\frac{dy}{dx}=\frac{\left(6x^2+3x+1\right)}{2y+1}$
$\left(-\frac{1}{x^3}\right)^5$
$-67b+6<9b+43$
$9x^4-60x^2+100$
$-\left(5x-2y+5\right)-\left(3y-5x+35\right)$
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