$4+7+2-7-3$
$\frac{x+3}{5}=1$
$9x^2+48xu+64u^2$
$x^2\left(9x^2+6x-12\right)$
$\tan x\left(\csc\left(x\right)-\sin\left(x\right)\right)=\cos\left(x\right)$
$9^0-4$
$\frac{d^2}{dx^2}\frac{x^2-3x}{5x-2}$
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