$\left(7+t\right)^2$
$\int\frac{\sqrt{t}}{t+1}dt$
$\frac{6}{x^2+4x+3}$
$1-25x^2\le0$
$\:6\:cos\:2x$
$\frac{2x^2+x-3}{x-1}$
$1,5\cdot\left(\frac{\sin\left(24\right)+\cos\left(24\right)}{tan\left(33\right)}\right)$
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