$\frac{12}{11x+2}<8$
$\left(3a-2b+7c\right)+\left(-4^a+3c+2b\right)$
$8\tan\left(-x\right)\cos\left(x\right)$
$sin\:\left(a\right)+sin\:\left(2a\right)+\:sin\:\left(3a\right)=sin\:\left(2a\right)\left(1+2cos\:\left(a\right)\right)$
$7x^2+14x+3$
$-36+36-36$
$2xy+3^2-5xy\:-7x^2$
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