$\int\:\frac{x+1}{x^3+x^2-6x}\:dx$

$\lim_{x\to5}\left(\frac{\left(1+x\right)^3-1}{x^2-25}\right)$

$-12,43+8,51$

$\frac{d}{dx}\left(1000-.005x^2-.01y^2\right)$

$\left(1-a^2\right)-\left(9n^2-6an\right)$

$\int\left(e^{\frac{x}{3}}\right)dx$

$\sec^2\left(3x\right)+2\tan\left(3x\right)-1=4$