$f\left(x\right)=\frac{1}{\left(x-2\right)\left(x+1\right)}$
$x^2-x-4xy^2$
$3.03125\cdot0.33$
$\lim_{x\to\infty}\left(\frac{3x^3+x+3}{x^2-3x}\right)$
$\frac{x^3+x^2+x}{x^3-x^2-x-2}$
$\lim_{x\to\infty}\left(\frac{7x-4}{\sqrt{6x^3+5x}}\right)$
$-4:-12$
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