$\frac{12x+7}{x^2-x-2}$
$\left(x^5+3\right)\left(x^5+2\right)$
$-400-2020$
$-6x\ge-18$
$\left(\frac{8-2y}{3}\right)^2$
$3-\left(-2+11-\left(4-15-7\right)\right)-2+\left(-3-\left(5-26-1\right)+2\right)\:$
$3a\left[2\right]-6ab$
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