$\frac{\cos\left(3x\right)}{\sin2x}$
$36x^2y^4-49x^4y^4$
$2-1^{3}-3-1$
$\cos\left(9\right)^2-\sin\left(9\right)^2$
$5\left(6-5\left(1\left(8-9\right)\right)\right)$
$\left(\left(3x+5\right)+2y\right)^2$
$\frac{4}{x-3}+\frac{6}{x-4}=\frac{x^2-25}{x^2-7x+12}$
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