$\left(3\right)^4-18\left(3\right)^2+81$
$5x-1=2x+20$
$5x-4y\sqrt{x^2+1}\frac{dy}{dx}=0$
$\sqrt{6-4}$
$2ab-a^2$
$4ab\:-\:10ab\:+\:5ac\:-\:3ac$
$\frac{dy}{dx}=\frac{x}{\sqrt{y}}$
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