$\:\frac{x}{2}=-16$
$\frac{\left(-6x^6+12x^5+3x^3-4x+16\right)}{x^3-x+3}$
$x^2+7x+10\cdot x+3$
$\frac{1}{2}x^2+\frac{1}{3}xy-\frac{1}{2}xy+\frac{1}{4}x^2$
$\frac{x^2+6x-3}{x+1}$
$-5\left(2k+1\right)+6\left(-3-5k\right)$
$\left(2d+m^2\right)^2$
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