$\left(m^4+2y\right)^2$
$\int\left(\frac{0.06t^2}{6+0.02t^3}\right)dx$
$-7+7+2-12-3+8$
$\int x\left(4w-1\right)^3dw$
$8\:-\:\left(\:4\:\cdot\:1\:-\:5\:\right)$
$\int_0^2\left(x^2\right)-\left(x-2\right)dx$
$-1+6-3$
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