$3,2\cdot7,5$
$\frac{\left(x^2+4x+3\right)}{\sqrt{x}}$
$\frac{x^5\cdot x^{-3}}{x^{-5}}$
$x^2\left(-3x^2\right)$
$-2x+7<23$
$6\cdot\left(-2\right)\cdot\left(-2\right)$
$\frac{dy}{dx}=\frac{x}{y\left(1+x^2\right)}$
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