$x-2\cdot x+2\cdot x$
$\frac{1+\tan\left(b\right)}{1+\cot\left(b\right)}=\tan\left(b\right)$
$\left(\frac{3}{4}x^2+\frac{1}{8}b^2\right)\left(\frac{03}{4}x^2-\frac{1}{8}b^2\right)$
$-\frac{2}{\left(2x+3\right)^2}$
$\sqrt[3]{b^4d^6}f^5$
$\frac{4}{9}m^2-25n^2$
$4\left(-15-3b\right)-4\left(-b+5\right)$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!