$7^6\:x\:7^1$
$2\left(16+13\right)$
$\frac{x}{a}+\frac{y}{b}=1$
$\int\frac{x+6}{x^2-4}dx$
$\frac{x}{7}+12=-19$
$\int-4e^{8x+4}dx$
$\lim_{x\to0}\left(\left(\frac{e^x+x^2+2x-1}{3x^2}\right)\right)$
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