$2x^2-12x+14=3x^2-20x+21$
$1-1,3$
$3\int\left(\frac{x^2}{x+4}\right)du$
$\lim_{x\to0}\left(\frac{x^3-1}{x^3+2x^2-3x}\right)$
$\int\tan\left(3x\right)\sec^2\left(3x\right)dx$
$\left(-2\right)\left(-8\right)\left(-10\right)$
$\left(-x^a\right)\left(-x^{a+2}\right)$
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