$\lim_{x\to0}\left(\frac{4x}{\sqrt{2x+25}-25}\right)$
$\left(x+5\right)\left(x+12\right)$
$x^8-1\:sobre\:1\:+\:x^4$
$9x^2\cdot b^2-25$
$\frac{\frac{3}{2}a^6}{\frac{2}{5}a^4}$
$\frac{d}{dx}\left(3x^2+5x\right)^3$
$a=8,\:b=6,\:c=6$
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