$\left(-8x^2y\right)\left(-3x^4y^5\right)^4$
$\frac{\left(5x+7\right)}{3}-4>5$
$\int\:\frac{r^2}{\sqrt[3]{2-3r}}dr$
$3^3\cdot\sqrt{4}-4^2$
$\left(3y+4\right)\left(3y-2\right)$
$x+y+z=12$
$9+4+12+5-1+8-1$
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