$2\left(2\right)+2\left(2^3+5\right)-\left(3-1\right)^2\left(2^2-2\right)^2$

$\frac{1\:-\:cos\:\theta}{sin\left(\theta\right)}=\:csc\:\theta\:-\:cot\:\theta$

$-\left(\frac{-11}{-1}\right)$

$-4x+\frac{10}{x};\:x=5$

$10y+8=-6+9y$

$y'-x^3=x^3y$

$\left(2x^4-3x\right)\left(3x+2\right)$