$\cos^2\left(x\right)=\sin^2\left(x\right)\cdot\cos^2\left(x\right)+\cos^5\left(x\right)$
$\lim\:_{x\to\:-4}-\frac{\left(2x+13\right)}{\left(x+4\right)^4}$
$4x^2+14x+10$
$\int_2^{\infty}\left(\frac{1}{\sqrt{x^4-1}}\right)dx$
$\frac{64^4}{64^3}$
$-10-3\cdot7$
$1-4g+g-7$
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