$\frac{m}{12}=-7$
$6\sqrt[3]{m}-10\sqrt[3]{m}$
$\frac{27x^{-9}}{18x^{-3}}$
$\left(8x^3+9m^3\right)^2$
$2\:cos^2\left(x^2+2\right)$
$in\left(x-7\right)-in\left(x+11\right)$
$y=\frac{\left(x-1\right)}{\left(x^2-5x+6\right)}$
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