$\int e^vdv$

$\frac{5\left(x-3\right)}{3\:}<\frac{3\left(6-2x\right)}{2}$

$\int\left(\frac{2}{e^{-t}}\right)dx$

$3+5+6+3+1$

$\int\frac{\sec^{2}x}{\tan^{2}x}dx$

$\frac{\left(\sqrt{x^2+5}\right)}{\left(x\right)}\left(\frac{dy}{dx}\right)=\frac{\left(2\right)}{y\left(e^{y^2}\right)}$

$\left(3m^2-3\right)\left(3m^2-6\right)$