$4a^2+12a+8=-2$
$\left(2x^4-3x^3-4x^2+x-18\right)\:\left(x+3\right)$
$\left(2a-5\right)\left(5+2a\right)$
$12x^2-60x+72=0$
$\left(a^2+a+b\right)\left(a^2+a+b\right)$
$\sqrt[32]{1+\left(9^8-1\right)\left(9^8+1\right)}$
$\lim_{x\to\infty}\left(\frac{17x}{17x+4}\right)^{3x}$
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