$\frac{dy}{dx}\left(3y^2=\frac{\left(2x-5\right)}{2x+5}\right)$
$400-127$
$3\csc\left(x\right)+\frac{5}{x}$
$\sqrt{\left(5x^4-x^2+10\right)}\left(10x^3-x\right)$
$\lim_{x\to\infty}\left(1+2x\right)^{\frac{13}{2\ln\left(x\right)}}$
$y^'=\frac{y}{1+x^2}$
$x^2-9<10$
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