$\left(4^2\right)\left(4^2\right)$
$\frac{dy}{dx}=\frac{x+4}{y-2}$
$3+-2-6+5-9-12+-13$
$-1+3+7\cdot4$
$\sqrt { 3 x + 4 } = 5$
$\int_{-1}^2\left(5+4x\right)\left(-1+2x\right)dx$
$\frac{\cot\left(x\right)+\csc\left(x\right)}{1+\cos\left(x\right)}$
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