$\left(10\right)\left(-34\right)$
$-5\cdot7+\left(12-5\cdot\left(-3\right)\right)$
$8a+12b^{2}$
$25-40m^2+16m^4$
$3x_-3$
$\int x^2\left(4x^3+5\right)^2dx$
$\frac{\cos\left(90-x\right)\cos\left(x\right)}{\cot\left(x\right)}=1-\sin^2\left(x\right)$
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