$30+5+8-3+1-4$

$-997-2004$

$\int\frac{x}{\sqrt{6x+x^2}}dx$

$g\left(x\right)=\frac{\left(5x^2+x+2\right)}{\left(x+1\right)\left(x^2+1\right)}$

$\frac{3x^4+2x^3-5x^2-7}{x+2}$

$4x^2+x=3$

$\int_{\frac{\sqrt{2}}{2}}^1\left(\frac{1}{\arctan\left(x\right)\left(1+x^2\right)}\right)dx$