$\frac{\left(15\right)\left(4\right)\left(-8\right)}{\left(-3\right)\left(-4\right)}$
$\lim_{x\to\infty}\left(1+\frac{1}{x^3}\right)^x$
$9a^2.42a+49$
$\left(8w^3b^9\right)^2$
$\left(25m^2-4\right)$
$\left(c-6d\right)^6$
$2x+4<-1$
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