$x^2-12\ge x$
$\log_{x+3}\left(x+5\right)=2$
$-2\left(m-2\right)=6$
$\lim_{x\to0}\left(\frac{cosx+e^x-2}{e^x-1}\right)$
$ax+az+bx+bz$
$x^2\ge2+x$
$\left(x+5\right)\left(x+2\right)=\left(2x+4\right)\left(x-3\right)$
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