$\lim_{x\to0}\left(\frac{sec^2\left(x\right)-\cos\left(x\right)}{x^3}\right)$
$y'''-43y'=0$
$14x^2-21x+6x-9$
$x\:\ge\:2x\:-\:1$
$\left(4x+1\right)dx\:+\left(5y\:+\:7\right)dy$
$6x+7\le13$
$5x^3+135$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!