$5x+15\le\:\:55$
$\frac{3a}{a^4}$
$\frac{3x+10}{x+7\:}<\:7$
$\int_0^{\frac{\pi}{4}}\tan^{12}\left(x\right)\sec^2\left(x\right)dx$
$4\left(x-2y+3z\right)$
$-3^2-5\left(-3\right)\left(2\right)+2^2$
$2x-\frac{y}{7}+\frac{1}{3}=\frac{2}{3}$
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