$\lim_{x\to3}\left(\frac{x^2-9+5\ln\left(2x^2-6x+1\right)}{e^{-x+3}-1}\right)$
$216x^9+125y^3$
$6-7m^2+4n^2-8-9m^2-n^2$
$\frac{dy}{dx}+\frac{y}{x}=x^3+y^2$
$\lim_{x\to\infty}\left(\frac{x^3-4x^2+8}{2x-6x^2}\right)$
$u=x+y^3-3$
$\frac{1+sin^2\left(x\right)}{1+cos^2\left(x\right)}=sin^2\left(x\right)+sin^2\left(x\right)$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!