$-4\cdot2-7$
$\left(2x^2y\right)\left(3x^4y^2\right)\left(-\frac{5}{18}xyz\right)$
$\int\frac{x}{\left(3x^2-4\right)^2}dx$
$\left(3ax-4\right)^2$
$-2x-5y=2x-5$
$\sqrt{169-56}$
$\frac{dy}{dx}=3x^2-8x+5$
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