$2x^2+8x-15=0$
$x+5=x+3$
$\left(\frac{b^{\frac{5}{2}}}{\sqrt{b}}\right)-\left(4b^4\right)^{\frac{1}{2}}$
$what\:is\:\left|-7\right|$
$\frac{x^2-3x-3}{x^2-2x+1}$
$\sqrt{398.94}$
$\left(2^3x^2\right)^5$
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