$f^2+40-f^2$
$\frac{3x^2+x}{5x^2+10x}$
$\frac{dx}{dt}=\frac{3}{x}$
$\frac{\left(16a^6b\:^{-3}\right)}{-4a^6b^3}$
$\frac{x^3-x^2+2x-1}{x^3+1}$
$-4-\left(4-9+3\right)-15$
$y^2=25$
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