$\lim_{x\to\infty}\left(\frac{x^8}{2^x}\right)$
$25v^2+60v+36$
$\frac{2s-3}{7}=5$
$\frac{a^{-7}}{a^{2b}}$
$\int3x^2cdx$
$\frac{\left(x-5\right)}{\left(x+2\right)}\ge8$
$\int\left(\frac{3x+5}{x^2+x-5}\right)dx$
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