$\left(y^3+4\right)^3$
$\frac{\left(x^3-125\right)}{x^2+5\:x\:+25}$
$3\sin^2\left(x\right)\cos\left(3x\right)=3\sin^2\left(x\right)\cos\left(4x\right)$
$4a^2-5a+3$
$\frac{5x+3}{x^3-5x^2+6x}$
$\left(2a^3+3b\right)^2$
$\int\frac{5x^2-3x+1}{2x-1}dx$
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