$\frac{x^8-256}{x^2+4}$
$3\:x\:\left(-4\right)$
$\frac{dy}{dx}3x^2\cdot y=x^2$
$\lim_{x\to\infty}\left(x-5\right)^{\frac{2}{x}}$
$-\left(-2x+6\right)+3x$
$2y^23x$
$\frac{dy}{dx}=\left(x+1\right)^{\frac{5}{2}}+\frac{2y}{x+1}$
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