$\left(2x\right)^2-10x+25$
$4c^2-20cd+25d^2$
$\left(2.5a+3e\right)\left(2.5a-3e\right)$
$\frac{d^8}{dx^8}\left(3e^{-\frac{x}{4}}\right)$
$5x+10=95$
$9\cot^2\theta\:-4=0$
$x-5>2x-6$
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