$1.8^4\cdot8^8$
$6\left(\frac{t}{t-1}\right)^5$
$\sqrt[5]{38-6}$
$\int\left(-\frac{13}{\left(4-3x\right)^8}\right)dx$
$\frac{9m^2n}{-4mn^2}$
$\left(2x+9\right)^3$
$\frac{\left(5^5\:+\:7\right)}{\left(x+2\right)}\:$
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