$3x-27\leq21$
$2308-2\cdot\:2600$
$\lim_{x\to\infty}\left(1+\frac{3x}{x^2+1}\right)^{4x}$
$\left(9x-1\right)^2$
$29+\left(-6+13\right)-\left(-28\right)$
$12^9$
$6mn^2+18m^2n^2$
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