$\left(\frac{3bc^5}{a^2}\right)^{-2}\:\left(\frac{a^5b}{5c}\right)^3$
$3x^2-x+6$
$\left(-2\right)-\left(-13\right)+\left(-7\right)$
$\frac{9x^2}{16}-\frac{1}{16}$
$\left(2x+1\right)^2-2x\left(x-3\right)=6x^2+6x+2-\left(2x-1\right)^2$
$y'=\left(15x^2+4\right)\left(6y+5\right)$
$\frac{dy}{dx}=e^ysin\left(x\right)$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!