$4-6x\ge x-10$
$\left(x-6\right)\left(x+6\right)\left(x^2+1\right)$
$\frac{\left(2x^3-5x^2+x+2\right)}{\left(x-2\right)}$
$\frac{-x^2-2}{-x^2-2}$
$24x+7x-8-16x+9x+14-4x+32x-22$
$28+56t+28w$
$\left(3b^2+2c\right)^3$
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