$-4x^2\cdot\left(-x\right)^2$
$12\cdot14$
$-6y+7-7+4x^2-6x-3x^2+7y$
$2x-y=-4$
$\frac{d^3}{dx^3}\:\left(\frac{3}{\left(x-1\right)^2}\right)$
$x^2-2x+2=3$
$\frac{\left(8\cdot7+5\cdot\left(-8\right)\right)}{\left(-4\right)}$
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