$1-25x^2$
$y=\sqrt[3]{x}-x^4+\frac{3}{x-5}+2x$
$\int\frac{\left(10x^5-8x^2\right)}{x^2}dx$
$\frac{5}{x}+\frac{2}{3}=-\frac{3}{x}$
$\int_0^2\left(x+2\right)\left(\frac{4}{1+x^2}-2\right)dx$
$x^3-x^2-9x-6$
$m^4+12m^{4\:}$
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