$\lim_{x\to+\infty}\left(\frac{3x+4}{2x^2-5}\right)$

$\left(-7x^3+6x^2\right)\left(9x^{10}-6x^2\right)$

$\tan\left(x\right)^2+\sec\left(x\right)^2-3\:=\:0$

$\left(8x^2+y\right)^2$

$\left(\frac{4}{7}x^5y^2z-7x^3yz\right)\left(\frac{4}{7}x^5y^2z+7x^3yz\right)$

$\frac{x^3-2x^2+2x+1}{x-2}$

$3x-x^2\ge\:6$