$\int\frac{x^2}{\sqrt[4]{x^3-1}}dx$
$4 + 5 - 3 + 5 - 6 + 2 + 3$
$\left(x+2\right)\left(x^2+3x-5\right)$
$\left(x+36\right)^2$
$\frac{a^2}{2b}+\frac{2b^2}{a}$
$\frac{x^2-4x-20}{x+3}$
$8x+10x-4xy-5y$
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