$8x^2-4x-5=0$

$2x^6-12x^4$

$\left(3+x^{4}\right)\frac{dy}{dx}=\frac{x^{3}}{y}$

$\int\frac{4\cos\left(x\right)+5\sin\left(x\right)}{4\sin\left(x\right)-5\cos\left(x\right)}dx$

$6\left(\frac{x+1}{8}-\frac{1}{16}\left(2x-3\right)\right)$

$\left(\frac{2}{3\:x}+y\right)^2$

$dx+e^{4x}dy=0$