$\frac{3+\frac{2}{y^3}-3y^4}{9y^4-\frac{5}{y^2}-3}$
$\left(\frac{2}{3}x+\frac{1}{2}y-4\right)+\left(\frac{1}{4}x-\frac{5}{6}y-\frac{1}{2}\right)+\left(\frac{3}{4}x-\frac{5}{3}y\right)$
$y^3+sy^2$
$2\left(x+3\right)=98$
$24x^3w+15x^2y-9x$
$-56:-23$
$35\cdot0.00099$
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