$\:\frac{\left(2t+1\right)}{2\left(t^2+t\right)}$
$-18x=-360$
$\frac{1}{secx+1}-\frac{1}{secx-1}$
$6x-30$
$3\cos=5$
$\left(2x+\frac{4}{5}\right)\left(2x-\frac{4}{5}\right)$
$-\left(4-\sin^2\left(x\right)\right)$
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